Earth Sandwich / City antipodes / Amritsar
Antipode finder · India
The antipode of
Amritsar.
Draw a straight line from Amritsar (31.62° N, 74.88° E) through the centre of the Earth and it comes out at 31.62° S, 105.12° W, in the South Pacific Ocean, 573 km from the nearest dry land, off the coast of Chile. The other slice of an Earth sandwich would sink.
- Amritsar
- 31.62° N, 74.88° E · about 200 m above sea level · 1,159,227 people
- Antipode
- 31.62° S, 105.12° W
- What is there
- The South Pacific Ocean; the sea floor there lies about 3,480 m below the surface
- Nearest dry land
- 573 km from the antipode, on the coast of Chile
- Nearest town
- Hanga Roa, Chile · 648 km from the antipode
- Nearest big city
- Santiago · 3,223 km from the antipode
- Sandwich verdict
- SOGGY the other slice lands in open water
- Nearest exact spot
- 641 km away, near Jaisalmer, India ⇄ near Hanga Roa, Chile
Can you make an Earth sandwich from Amritsar?
No, not from Amritsar itself. The other slice would land in the South Pacific Ocean, 573 km from the nearest dry land (Chile), where the sea floor lies about 3,480 m below the surface. Boats do not count (Sandwich Law § 1.3).
The nearest place from which an exact Earth sandwich is possible is 641 km from Amritsar, 25 km from Jaisalmer, India. Its other slice would go down 20 km from Hanga Roa, Chile.
How this was worked out: the antipode flips the latitude and moves the longitude by 180°. Land or sea comes from the OpenStreetMap coastline the map uses; the sandwich verdict and elevations come from the verifier's 0.2° grid (Natural Earth land, ETOPO 2022 relief); water names from Natural Earth; towns and populations from GeoNames. The city's position is GeoNames' point for it; a big city's suburbs spread tens of kilometres around that point, and the figures move with them. Generated 2026-09-29.